How much chocolate is in a spherical chocolate truffle with a radius of 12 mm? Use 3.14 as an approximation for pi. Round your answer to the nearest hundredth, if necessary..

1 answer

To find the amount of chocolate in a spherical chocolate truffle, we will calculate the volume of the sphere using the formula for the volume of a sphere:

\[ V = \frac{4}{3} \pi r^3 \]

where \( V \) is the volume and \( r \) is the radius.

Given:

  • Radius \( r = 12 \) mm
  • Using \( \pi \approx 3.14 \)

Now we can plug in the values:

  1. Calculate \( r^3 \):

\[ r^3 = 12^3 = 12 \times 12 \times 12 = 144 \times 12 = 1728 \text{ mm}^3 \]

  1. Now substitute \( r^3 \) into the volume formula:

\[ V = \frac{4}{3} \times 3.14 \times 1728 \]

  1. Calculate \( \frac{4}{3} \times 3.14 \):

\[ \frac{4}{3} \times 3.14 \approx 4.18667 \]

  1. Now calculate the volume \( V \):

\[ V \approx 4.18667 \times 1728 \]

  1. Carrying out the multiplication:

\[ V \approx 7205.51456 \text{ mm}^3 \]

Finally, rounding to the nearest hundredth gives:

\[ V \approx 7205.51 \text{ mm}^3 \]

Thus, the volume of chocolate in the spherical chocolate truffle is approximately 7205.51 mm³.