To find the volume of a sphere, we use the formula:
\[ V = \frac{4}{3} \pi r^3 \]
where \( V \) is the volume and \( r \) is the radius of the sphere.
First, we need to find the radius of the basketball. Given that the diameter is 9 inches, the radius \( r \) is half of the diameter:
\[ r = \frac{9}{2} = 4.5 \text{ inches} \]
Now, we can plug the radius and the approximation for \(\pi\) (3.14) into the volume formula:
\[ V = \frac{4}{3} \times 3.14 \times (4.5)^3 \]
First, we calculate \( (4.5)^3 \):
\[ (4.5)^3 = 4.5 \times 4.5 \times 4.5 = 20.25 \times 4.5 \approx 91.125 \]
Now substitute this back into the volume formula:
\[ V = \frac{4}{3} \times 3.14 \times 91.125 \]
Calculate \( \frac{4}{3} \times 3.14 \):
\[ \frac{4}{3} \times 3.14 \approx 4.18667 \]
Now multiply this by \( 91.125 \):
\[ V \approx 4.18667 \times 91.125 \approx 381.5 \]
Rounding to the nearest tenth:
\[ V \approx 381.5 \text{ in}^3 \]
Thus, the answer is:
381.5 in³