To find the volume of a sphere, you can use the formula:
\[ V = \frac{4}{3} \pi r^3 \]
where \( V \) is the volume and \( r \) is the radius of the sphere.
First, calculate the radius of the basketball. The diameter is 9.2 inches, so the radius is:
\[ r = \frac{d}{2} = \frac{9.2}{2} = 4.6 \text{ inches} \]
Now, substitute the radius and \(\pi \approx 3.14\) into the volume formula:
\[ V = \frac{4}{3} \times 3.14 \times (4.6)^3 \]
Calculate \( (4.6)^3 \):
\[ (4.6)^3 = 97.336 \]
Next, plug this value back into the volume formula:
\[ V = \frac{4}{3} \times 3.14 \times 97.336 \]
Now calculate \( \frac{4}{3} \times 3.14\):
\[ \frac{4}{3} \times 3.14 \approx 4.18667 \]
Next, multiply this by \( 97.336 \):
\[ V \approx 4.18667 \times 97.336 \approx 407.51 \]
Rounding to the nearest hundredth:
\[ V \approx 407.51 \text{ in}^3 \]
Thus, the volume of the basketball is approximately 407.51 in³.