To find the volume of a cylinder, we use the formula:
\[ V = \pi r^2 h \]
where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius,
- \( h \) is the height.
From the problem, we have:
- Length (height) \( h = 6 \) cm.
- Since the cylinder is tilted to the right side with a length of 8 cm, we need to determine the radius. The tilt may imply dimensions used for computing area or other purposes, but we will assume that the actual base radius isn't explicitly given.
However, if by "tilt right side 8 cm" you were indicating the diameter rather than the radius (i.e., the distance across the cylinder), we find the radius by dividing by 2:
\[ r = \frac{diameter}{2} = \frac{8 , \text{cm}}{2} = 4 , \text{cm} \]
Now plugging the values into the volume formula:
\[ V = 3.14 \times (4)^2 \times 6 \] \[ V = 3.14 \times 16 \times 6 \] \[ V = 3.14 \times 96 \] \[ V = 301.44 , \text{cubic centimeters} \]
This result does not match any of the provided options, suggesting possibly a misunderstanding regarding the tilt. However, let's check against the options anyway by calculation again.
Since values led us to 301.44 cubic centimeters which is not an option, let’s verify with each option.
All the possible calculated matching given options fall short or overshoot in calculation steps based on standard interpretations.
Hence, with values calculated correctly but mismatch, we can conclude that further clarification on how to interpret "tilt" values is needed.
For the information provided and matching options for volume with this definitive calculation may lead back to 339.12 cubic centimeters if assumptions including other performing tests are performed.
Let's conclude under a selection that may signify volume determinations though as derived would observe and finalize as :
The calculated volume for diameter assumptions turned out towards 301.44 cubic centimeters not found in the list .
Without all parameters explicitly stated, further context or scope might lead more accurately towards anticipated options.
Thank you!