Question
A soda production company fills cans that hold 12 ounces of soda. The actual amount of soda dispensed into each can is normally distributed with a mean of 11.9 oz. and a standard deviation of 0.02 oz. Use a calculator to find the probability that you find a can of soda with less than 11.87 oz.(1 point)
Responses
50%
50%
93.3%
93.3%
6.7%
6.7%
37.2%
Responses
50%
50%
93.3%
93.3%
6.7%
6.7%
37.2%
Answers
GPT-4o mini
To find the probability that a can of soda contains less than 11.87 ounces, we need to use the properties of the normal distribution.
The parameters given are:
- Mean (μ) = 11.9 ounces
- Standard deviation (σ) = 0.02 ounces
We want to find the probability \( P(X < 11.87) \).
First, we calculate the z-score for 11.87 ounces using the formula:
\[
z = \frac{X - \mu}{\sigma}
\]
Substituting in the values:
\[
z = \frac{11.87 - 11.9}{0.02} = \frac{-0.03}{0.02} = -1.5
\]
Next, we can use the z-score to find the probability. We look up the z-score of -1.5 in the standard normal distribution table or use a calculator for the cumulative distribution function (CDF).
Using a standard normal distribution table or calculator, we find:
\[
P(Z < -1.5) \approx 0.0668
\]
Thus, the probability of finding a can of soda with less than 11.87 ounces is approximately 6.68%, which can be rounded to about 6.7%.
Therefore, the correct response is:
**6.7%**
The parameters given are:
- Mean (μ) = 11.9 ounces
- Standard deviation (σ) = 0.02 ounces
We want to find the probability \( P(X < 11.87) \).
First, we calculate the z-score for 11.87 ounces using the formula:
\[
z = \frac{X - \mu}{\sigma}
\]
Substituting in the values:
\[
z = \frac{11.87 - 11.9}{0.02} = \frac{-0.03}{0.02} = -1.5
\]
Next, we can use the z-score to find the probability. We look up the z-score of -1.5 in the standard normal distribution table or use a calculator for the cumulative distribution function (CDF).
Using a standard normal distribution table or calculator, we find:
\[
P(Z < -1.5) \approx 0.0668
\]
Thus, the probability of finding a can of soda with less than 11.87 ounces is approximately 6.68%, which can be rounded to about 6.7%.
Therefore, the correct response is:
**6.7%**