Question
A cone-shaped container on a farm is used for storing animal feed. The container has a radius of 4 ft and a height of 12 ft. The volume of feed, in cubic feet, this container can store is:
Answers
GPT-4o mini
To calculate the volume of a cone, you can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height of the cone.
Given:
- Radius \( r = 4 \) ft
- Height \( h = 12 \) ft
Now, substitute the values into the formula:
\[
V = \frac{1}{3} \pi (4)^2 (12)
\]
First, calculate \( (4)^2 \):
\[
(4)^2 = 16
\]
Now, substitute back into the equation:
\[
V = \frac{1}{3} \pi (16)(12)
\]
Next, calculate \( 16 \times 12 \):
\[
16 \times 12 = 192
\]
Now substitute this value back into the volume formula:
\[
V = \frac{1}{3} \pi (192)
\]
Now compute \( \frac{192}{3} \):
\[
\frac{192}{3} = 64
\]
Thus, the volume of the cone is:
\[
V = 64\pi
\]
If we want a numerical approximation, we can use \( \pi \approx 3.14 \):
\[
V \approx 64 \times 3.14 = 200.96
\]
Therefore, the volume of the feed container is approximately:
\[
\boxed{200.96} \text{ cubic feet}
\]
And the exact volume is:
\[
\boxed{64\pi} \text{ cubic feet}
\]
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height of the cone.
Given:
- Radius \( r = 4 \) ft
- Height \( h = 12 \) ft
Now, substitute the values into the formula:
\[
V = \frac{1}{3} \pi (4)^2 (12)
\]
First, calculate \( (4)^2 \):
\[
(4)^2 = 16
\]
Now, substitute back into the equation:
\[
V = \frac{1}{3} \pi (16)(12)
\]
Next, calculate \( 16 \times 12 \):
\[
16 \times 12 = 192
\]
Now substitute this value back into the volume formula:
\[
V = \frac{1}{3} \pi (192)
\]
Now compute \( \frac{192}{3} \):
\[
\frac{192}{3} = 64
\]
Thus, the volume of the cone is:
\[
V = 64\pi
\]
If we want a numerical approximation, we can use \( \pi \approx 3.14 \):
\[
V \approx 64 \times 3.14 = 200.96
\]
Therefore, the volume of the feed container is approximately:
\[
\boxed{200.96} \text{ cubic feet}
\]
And the exact volume is:
\[
\boxed{64\pi} \text{ cubic feet}
\]