Question
A sphere with a diameter of 13 millimeters
Which measurements is the closest to the volume of the marble in cubic millimeters?
answers:
1,150 mm^3
836 mm^3
6,902 mm 3
9,203 mm34
Which measurements is the closest to the volume of the marble in cubic millimeters?
answers:
1,150 mm^3
836 mm^3
6,902 mm 3
9,203 mm34
Answers
GPT-4o mini
To find the volume of a sphere, you can use the formula:
\[
V = \frac{4}{3} \pi r^3
\]
where \( V \) is the volume and \( r \) is the radius of the sphere.
1. **Calculate the radius**: The radius is half of the diameter. Given that the diameter is 13 millimeters, the radius is:
\[
r = \frac{13}{2} = 6.5 \text{ mm}
\]
2. **Calculate the volume using the formula**:
\[
V = \frac{4}{3} \pi (6.5)^3
\]
3. **Calculate \( (6.5)^3 \)**:
\[
(6.5)^3 = 6.5 \times 6.5 \times 6.5 = 274.625
\]
4. **Substituting into the volume formula**:
\[
V = \frac{4}{3} \pi (274.625)
\]
5. **Calculate the volume**:
Using \( \pi \approx 3.14159 \):
\[
V \approx \frac{4}{3} \times 3.14159 \times 274.625 \approx \frac{4 \times 3.14159 \times 274.625}{3}
\]
Calculating this step by step:
\[
4 \times 3.14159 \approx 12.56636
\]
Then multiply by \( 274.625 \):
\[
12.56636 \times 274.625 \approx 3457.791
\]
Now divide by 3:
\[
\frac{3457.791}{3} \approx 1152.597
\]
Thus, the volume of the marble is approximately:
\[
V \approx 1152.6 \text{ mm}^3
\]
The closest measurement to the calculated volume (1152.6 mm³) from the provided options is:
**1,150 mm³**.
\[
V = \frac{4}{3} \pi r^3
\]
where \( V \) is the volume and \( r \) is the radius of the sphere.
1. **Calculate the radius**: The radius is half of the diameter. Given that the diameter is 13 millimeters, the radius is:
\[
r = \frac{13}{2} = 6.5 \text{ mm}
\]
2. **Calculate the volume using the formula**:
\[
V = \frac{4}{3} \pi (6.5)^3
\]
3. **Calculate \( (6.5)^3 \)**:
\[
(6.5)^3 = 6.5 \times 6.5 \times 6.5 = 274.625
\]
4. **Substituting into the volume formula**:
\[
V = \frac{4}{3} \pi (274.625)
\]
5. **Calculate the volume**:
Using \( \pi \approx 3.14159 \):
\[
V \approx \frac{4}{3} \times 3.14159 \times 274.625 \approx \frac{4 \times 3.14159 \times 274.625}{3}
\]
Calculating this step by step:
\[
4 \times 3.14159 \approx 12.56636
\]
Then multiply by \( 274.625 \):
\[
12.56636 \times 274.625 \approx 3457.791
\]
Now divide by 3:
\[
\frac{3457.791}{3} \approx 1152.597
\]
Thus, the volume of the marble is approximately:
\[
V \approx 1152.6 \text{ mm}^3
\]
The closest measurement to the calculated volume (1152.6 mm³) from the provided options is:
**1,150 mm³**.