Question

Can YOU curl your tongue up on the sides? We are pretending that tongue-curling in humans is a dominant genetic trait. Suppose a man who is Tt for tongue-curling marries a woman who is also Tt for this trait. What are the possible genotypes and phenotypes of their children, and the percent chance for each? Genotype Phenotype (curl or no curl) Percent Chance (number only) TT Tt tt Word Bank: 7525no curlcurlcurl10050025

Answer 1

In this scenario, we can use a Punnett square to predict the possible genotypes and phenotypes of the children from two parents who are both Tt for the tongue-curling trait.

The genotypes for tongue-curling are:
- T (dominant allele for tongue-curling)
- t (recessive allele for no tongue-curling)

The possible gametes from each parent (Tt x Tt) are:
- Parent 1: T and t
- Parent 2: T and t

Setting up the Punnett square:

| | T | t |
|-----|-----|-----|
| **T** | TT | Tt |
| **t** | Tt | tt |

From the Punnett square, we can determine the following genotype ratios:
- 1 TT (homozygous dominant)
- 2 Tt (heterozygous)
- 1 tt (homozygous recessive)

So, the possible genotypes of their children and their corresponding phenotypes are:
- TT: curl (1)
- Tt: curl (2)
- tt: no curl (1)

Phenotype ratio:
- Curl (TT and Tt combined): 3 (1 TT + 2 Tt)
- No curl (tt): 1

Now, we'll convert these ratios into percentage chances:
- TT: 25%
- Tt: 50%
- tt: 25%

So, the final answers, including phenotype and percent chance, are:

- Genotype: **TT** - Phenotype: **curl** - Percent Chance: **25**
- Genotype: **Tt** - Phenotype: **curl** - Percent Chance: **50**
- Genotype: **tt** - Phenotype: **no curl** - Percent Chance: **25**