Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.

q = 55 StartRoot 5 EndRoot
q = -5Negative 5 StartRoot 5 Endroot
q = 33 StartRoot 5 Endroot
q = -3Negative 3 StartRoot 5 EndRoot
q = 2525 StartRoot 5 EndRoot

1 answer

To find the roots of the quadratic function \( f(q) = q^2 - 125 \), we need to set the function equal to zero:

\[ q^2 - 125 = 0 \]

This can be rewritten as:

\[ q^2 = 125 \]

Taking the square root of both sides, we find:

\[ q = \sqrt{125} \quad \text{or} \quad q = -\sqrt{125} \]

Since \( \sqrt{125} = \sqrt{25 \cdot 5} = 5\sqrt{5} \), the roots can be expressed as:

\[ q = 5\sqrt{5} \quad \text{and} \quad q = -5\sqrt{5} \]

Thus, the roots of the function are:

  • \( q = 5\sqrt{5} \)
  • \( q = -5\sqrt{5} \)

From your options, the correct choices are:

  • \( q = 55\sqrt{5} \) (this seems like a typo, it should be \( q = 5\sqrt{5} \))
  • \( q = -5\sqrt{5} \)

So the final roots are:

  1. \( q = 5\sqrt{5} \)
  2. \( q = -5\sqrt{5} \)