Question

Solve the factored quadratic equation (19x−3)(9+x)=0
(1 point)
Responses

{−9,319}
start set negative 9 comma 3 over 19 end set

{193,9}
start set 19 thirds comma 9 end set

{−9, 3}
{−9, 3}

{−9,193}

Answer 1

To solve the factored quadratic equation \((19x−3)(9+x)=0\), we set each factor equal to zero:

1. \(19x - 3 = 0\)
2. \(9 + x = 0\)

**For the first factor:**

\[
19x - 3 = 0
\]
\[
19x = 3
\]
\[
x = \frac{3}{19}
\]

**For the second factor:**

\[
9 + x = 0
\]
\[
x = -9
\]

Therefore, the solutions to the equation \((19x−3)(9+x)=0\) are:

\[
\left\{-9, \frac{3}{19}\right\}
\]

The correct response is:

\(\{−9, \frac{3}{19}\}\)

This matches with the option:

\(\{−9, \frac{3}{19}\}\)

So, the response would be:

**{−9, 3/19}**