Translate figure PQRS

Question

𝑃
𝑄
𝑅
𝑆
6 units down and 2 units to the right. What are the coordinates of P′
𝑃
′
?

(1 point)
Responses

(2, 0)
(
2
,

0
)
left parenthesis 2 comma 0 right parenthesis

(6, 0)
(
6
,

0
)
left parenthesis 6 comma 0 right parenthesis

(2, 12)
(
2
,

12
)
left parenthesis 2 comma 12 right parenthesis

(10, 4)
og cordinits of p 4x,6y

Answer 1

To find the coordinates of point \( P' \) after translating point \( P \) 6 units down and 2 units to the right, we need to start with the original coordinates of point \( P \).

Given that the coordinates of \( P \) are \( (4, 6) \):

1. Move 6 units down: This means we subtract 6 from the y-coordinate:
   • New y-coordinate: \( 6 - 6 = 0 \)
2. Move 2 units to the right: This means we add 2 to the x-coordinate:
   • New x-coordinate: \( 4 + 2 = 6 \)

So the new coordinates of \( P' \) would be \( (6, 0) \).

The correct response is: (6, 0) \( \left( 6, 0 \right) \)