Question
The pH of a chemical solution is given by the formula pH = -log10 [H+] where [H+] is the concentration of hydrogen ions in moles per liter. Values of pH range from 0 (acidic) to 14 (alkaline).
(a) what is the pH of the solution for which [H+] is 0.1?
(b) What happens to pH as the hydrogen ion concentration decreases?
(c)Determine the hydrogen ion concentration of an orange pH =3.8
(d) Determine the hydrogen ion concentration of human blood pH =7.4
All of these are simple log questions.
Are you having trouble with logs? For example, the answer to part (a) is just the -log(0.1).
I am. These are all log questions. And I think the main problem is how to put the question into my calculator. I am struggling the logs . Our teacher doesn't seem to teach things to our level.
For (a) use H+ = .01 in the formula to get
pH=-log10[.1] = -log10[10^-1]
For (b) you should see that the - sign before the log tells us the pH and H+ are inversely related.
For (c) set pH=3.8 in the formula and solve for H+
3.8=-log10[H+]
and for (d) 7.4=-log10[H+], so solve for H+.
(a) what is the pH of the solution for which [H+] is 0.1?
(b) What happens to pH as the hydrogen ion concentration decreases?
(c)Determine the hydrogen ion concentration of an orange pH =3.8
(d) Determine the hydrogen ion concentration of human blood pH =7.4
All of these are simple log questions.
Are you having trouble with logs? For example, the answer to part (a) is just the -log(0.1).
I am. These are all log questions. And I think the main problem is how to put the question into my calculator. I am struggling the logs . Our teacher doesn't seem to teach things to our level.
For (a) use H+ = .01 in the formula to get
pH=-log10[.1] = -log10[10^-1]
For (b) you should see that the - sign before the log tells us the pH and H+ are inversely related.
For (c) set pH=3.8 in the formula and solve for H+
3.8=-log10[H+]
and for (d) 7.4=-log10[H+], so solve for H+.
Answers
Hope this helps!
Related Questions
I can't calculate 1 as the answer given to the following problem. I keep getting 2. Can you show me...
If log10^9=0.95 and log10^2=0.30, find the following:
1. log10^9/2
2. log10^3
3. log10^36
4. l...
Gien that Log10^2 = 0.3010, log10^3= 0.4771and log10^5 =0.6990 find log 10^35 - log10^17.5
Given that log10^2 = 0.3010,log10^3= 0.4771 and log10^5=0.6990 find Log10^6.5 +Log10^4