Question
A student rides her bicycle down a hill. Together, she and the bicycle have a mass of 56 kilograms. She is moving at 11 meters per second. What is her kinetic energy?(1 point)
Responses
6,776 J
6,776 J
17,248 J
17,248 J
3,388 J
3,388 J
13,552 J
Responses
6,776 J
6,776 J
17,248 J
17,248 J
3,388 J
3,388 J
13,552 J
Answers
GPT-4o mini
The kinetic energy (KE) of an object can be calculated using the formula:
\[
KE = \frac{1}{2} mv^2
\]
where \( m \) is the mass of the object and \( v \) is its velocity.
In this case, the mass \( m = 56 \) kg and the velocity \( v = 11 \) m/s.
Now, we can calculate the kinetic energy:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times (11 \, \text{m/s})^2
\]
First, calculate \( (11 \, \text{m/s})^2 \):
\[
(11 \, \text{m/s})^2 = 121 \, \text{m}^2/\text{s}^2
\]
Now substitute this back into the equation:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times 121 \, \text{m}^2/\text{s}^2
\]
Now calculate \( \frac{1}{2} \times 56 = 28 \):
\[
KE = 28 \, \text{kg} \times 121 \, \text{m}^2/\text{s}^2
\]
Now calculate \( 28 \times 121 \):
\[
28 \times 121 = 3,388 \, \text{J}
\]
So, the kinetic energy is:
\[
\boxed{3,388 \, \text{J}}
\]
\[
KE = \frac{1}{2} mv^2
\]
where \( m \) is the mass of the object and \( v \) is its velocity.
In this case, the mass \( m = 56 \) kg and the velocity \( v = 11 \) m/s.
Now, we can calculate the kinetic energy:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times (11 \, \text{m/s})^2
\]
First, calculate \( (11 \, \text{m/s})^2 \):
\[
(11 \, \text{m/s})^2 = 121 \, \text{m}^2/\text{s}^2
\]
Now substitute this back into the equation:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times 121 \, \text{m}^2/\text{s}^2
\]
Now calculate \( \frac{1}{2} \times 56 = 28 \):
\[
KE = 28 \, \text{kg} \times 121 \, \text{m}^2/\text{s}^2
\]
Now calculate \( 28 \times 121 \):
\[
28 \times 121 = 3,388 \, \text{J}
\]
So, the kinetic energy is:
\[
\boxed{3,388 \, \text{J}}
\]