Question

If a sound wave has a wavelength of 0.790 meters, and is travelling at a speed of 355 m/s, what is the period of oscillation for this wave?

2.22 x 10-3 s

280 s

449 s

1.59 x 10-3 s

Answer 1

To find the period of oscillation of a sound wave, we can use the formula that relates wave speed (\(v\)), wavelength (\(λ\)), and frequency (\(f\)):

\[
v = f \cdot λ
\]

We can rearrange this formula to find frequency:

\[
f = \frac{v}{λ}
\]

The period (\(T\)) of the wave is the reciprocal of the frequency:

\[
T = \frac{1}{f}
\]

Now, let's calculate the frequency first:

Given:
- Wavelength (\(λ\)) = 0.790 m
- Speed (\(v\)) = 355 m/s

Calculating the frequency:

\[
f = \frac{355 \, \text{m/s}}{0.790 \, \text{m}} \approx 449.37 \, \text{Hz}
\]

Now, we can find the period:

\[
T = \frac{1}{f} \approx \frac{1}{449.37} \approx 0.002224 \, \text{s} \approx 2.22 \times 10^{-3} \, \text{s}
\]

So, the period of oscillation for this wave is approximately \(2.22 \times 10^{-3}\) seconds.

Thus, the correct answer is:

**2.22 x 10-3 s**