Question
What is the wavelength of an E-note played in air where the speed of sound is 343 m/s? The frequency of E is 330 Hz.
673 m
1.04 m
0.96 m
1.96 m
673 m
1.04 m
0.96 m
1.96 m
Answers
GPT-4o mini
To calculate the wavelength of a sound wave, you can use the following formula:
\[
\text{Wavelength} (\lambda) = \frac{\text{Speed of Sound} (v)}{\text{Frequency} (f)}
\]
Given:
- Speed of Sound \( v = 343 \, \text{m/s} \)
- Frequency \( f = 330 \, \text{Hz} \)
Now substitute the values into the formula:
\[
\lambda = \frac{343 \, \text{m/s}}{330 \, \text{Hz}} \approx 1.04 \, \text{m}
\]
So the wavelength of the E-note played in air is approximately **1.04 m.**
\[
\text{Wavelength} (\lambda) = \frac{\text{Speed of Sound} (v)}{\text{Frequency} (f)}
\]
Given:
- Speed of Sound \( v = 343 \, \text{m/s} \)
- Frequency \( f = 330 \, \text{Hz} \)
Now substitute the values into the formula:
\[
\lambda = \frac{343 \, \text{m/s}}{330 \, \text{Hz}} \approx 1.04 \, \text{m}
\]
So the wavelength of the E-note played in air is approximately **1.04 m.**