Question
Question content area left
Part 1
Use the map shown below to find the distance between cities A and B to the nearest tenth.
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-6
-4
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2
4
6
8
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-2
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Upper BUpper A
A graph with horizontal x-axis from negative 10 to 10 in increments of 1 and vertical y-axis from negative 10 to 10 in increments of 1 has the following labels and points: A, (0,0); B, (6, 3).
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.
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Question content area right
Part 1
The distance is
enter your response here.
(Round to the nearest tenth as needed.)
Part 1
Use the map shown below to find the distance between cities A and B to the nearest tenth.
-10
-8
-6
-4
-2
2
4
6
8
10
-10
-8
-6
-4
-2
2
4
6
8
10
x
y
Upper BUpper A
A graph with horizontal x-axis from negative 10 to 10 in increments of 1 and vertical y-axis from negative 10 to 10 in increments of 1 has the following labels and points: A, (0,0); B, (6, 3).
.
.
.
Question content area right
Part 1
The distance is
enter your response here.
(Round to the nearest tenth as needed.)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the distance between points A(0, 0) and B(6, 3), we can use the distance formula:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here:
- \( (x_1, y_1) = (0, 0) \)
- \( (x_2, y_2) = (6, 3) \)
Plugging the coordinates into the formula:
\[
d = \sqrt{(6 - 0)^2 + (3 - 0)^2} \\
d = \sqrt{(6)^2 + (3)^2} \\
d = \sqrt{36 + 9} \\
d = \sqrt{45}
\]
Now, simplifying \(\sqrt{45}\):
\[
\sqrt{45} = \sqrt{9 \cdot 5} = 3\sqrt{5}
\]
Using a calculator to approximate \(\sqrt{5}\) (which is about 2.236):
\[
3\sqrt{5} \approx 3 \cdot 2.236 \approx 6.708
\]
Rounding to the nearest tenth gives us:
\[
\text{Distance} \approx 6.7
\]
So the distance between cities A and B is approximately **6.7**.
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here:
- \( (x_1, y_1) = (0, 0) \)
- \( (x_2, y_2) = (6, 3) \)
Plugging the coordinates into the formula:
\[
d = \sqrt{(6 - 0)^2 + (3 - 0)^2} \\
d = \sqrt{(6)^2 + (3)^2} \\
d = \sqrt{36 + 9} \\
d = \sqrt{45}
\]
Now, simplifying \(\sqrt{45}\):
\[
\sqrt{45} = \sqrt{9 \cdot 5} = 3\sqrt{5}
\]
Using a calculator to approximate \(\sqrt{5}\) (which is about 2.236):
\[
3\sqrt{5} \approx 3 \cdot 2.236 \approx 6.708
\]
Rounding to the nearest tenth gives us:
\[
\text{Distance} \approx 6.7
\]
So the distance between cities A and B is approximately **6.7**.
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