Question
the first quartile of a data set is 41, and the third quartile is 57. which of these values in the data set is an outlier?
A)73
B)39
C)83
D)19
A)73
B)39
C)83
D)19
Answers
Answered by
GPT-4o mini
To identify outliers in a data set using the first quartile (Q1) and the third quartile (Q3), we can apply the interquartile range (IQR) method.
1. Calculate the IQR:
\[
\text{IQR} = Q3 - Q1 = 57 - 41 = 16
\]
2. Determine the lower and upper bounds for outliers:
- Lower bound: \( Q1 - 1.5 \times \text{IQR} \)
- Upper bound: \( Q3 + 1.5 \times \text{IQR} \)
Let's calculate these bounds:
\[
\text{Lower bound} = 41 - 1.5 \times 16 = 41 - 24 = 17
\]
\[
\text{Upper bound} = 57 + 1.5 \times 16 = 57 + 24 = 81
\]
3. Identify outliers:
Any data point below 17 or above 81 is considered an outlier.
Now, let's examine the values provided:
- A) 73 (not an outlier)
- B) 39 (not an outlier)
- C) 83 (outlier since it's greater than 81)
- D) 19 (not an outlier)
Thus, the outlier in the data set is **C) 83**.
1. Calculate the IQR:
\[
\text{IQR} = Q3 - Q1 = 57 - 41 = 16
\]
2. Determine the lower and upper bounds for outliers:
- Lower bound: \( Q1 - 1.5 \times \text{IQR} \)
- Upper bound: \( Q3 + 1.5 \times \text{IQR} \)
Let's calculate these bounds:
\[
\text{Lower bound} = 41 - 1.5 \times 16 = 41 - 24 = 17
\]
\[
\text{Upper bound} = 57 + 1.5 \times 16 = 57 + 24 = 81
\]
3. Identify outliers:
Any data point below 17 or above 81 is considered an outlier.
Now, let's examine the values provided:
- A) 73 (not an outlier)
- B) 39 (not an outlier)
- C) 83 (outlier since it's greater than 81)
- D) 19 (not an outlier)
Thus, the outlier in the data set is **C) 83**.
There are no human answers yet. A form for humans to post answers is coming very soon!