Asked by Idk
Area is 3ft. Height is 2ft. We want to wrap this cylinder in gift wrapping paper. what is the total surface area rounded to the nearest hundredth?
Surface area:
PRISM S=Ph. S=ph+2b
Cylinder. SpiRh. S=2piRh+2piR^2
Surface area:
PRISM S=Ph. S=ph+2b
Cylinder. SpiRh. S=2piRh+2piR^2
Answers
Answered by
Idk
Wrong
Answered by
GPT-4o mini
To calculate the total surface area of a cylinder, we use the formula:
\[
S = 2\pi R h + 2\pi R^2
\]
where:
- \( S \) is the total surface area,
- \( R \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From the information given, the area (which I assume is the base area of the cylinder) is \( 3 \, \text{ft}^2 \), and the height \( h \) is \( 2 \, \text{ft} \).
The area of the base of a cylinder is given by:
\[
\text{Area}_{\text{base}} = \pi R^2
\]
Since we are given that the area of the base is \( 3 \, \text{ft}^2 \), we can set up the equation:
\[
\pi R^2 = 3
\]
To find \( R \), we need to solve for \( R^2 \):
\[
R^2 = \frac{3}{\pi}
\]
Then, we take the square root of both sides:
\[
R = \sqrt{\frac{3}{\pi}}
\]
Now, we can substitute \( R \) and \( h \) into the surface area formula.
First, let's calculate \( R \):
\[
R \approx \sqrt{\frac{3}{3.14159}} \approx \sqrt{0.95493} \approx 0.977
\]
Now, using \( R \approx 0.977 \, \text{ft} \) and \( h = 2 \, \text{ft} \):
Now, we compute the total surface area \( S \):
\[
S = 2\pi R h + 2\pi R^2
\]
Calculating each part:
1. **Lateral surface area**:
\[
2\pi R h = 2\pi (0.977)(2) \approx 2\pi (1.954) \approx 12.26 \, \text{ft}^2
\]
2. **Area of the two bases**:
\[
2\pi R^2 = 2\pi \left(\frac{3}{\pi}\right) = 2 \cdot 3 = 6 \, \text{ft}^2
\]
Adding both components together:
\[
S \approx 12.26 + 6 = 18.26 \, \text{ft}^2
\]
Thus, the total surface area of the cylinder, rounded to the nearest hundredth, is:
\[
\boxed{18.26 \, \text{ft}^2}
\]
\[
S = 2\pi R h + 2\pi R^2
\]
where:
- \( S \) is the total surface area,
- \( R \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From the information given, the area (which I assume is the base area of the cylinder) is \( 3 \, \text{ft}^2 \), and the height \( h \) is \( 2 \, \text{ft} \).
The area of the base of a cylinder is given by:
\[
\text{Area}_{\text{base}} = \pi R^2
\]
Since we are given that the area of the base is \( 3 \, \text{ft}^2 \), we can set up the equation:
\[
\pi R^2 = 3
\]
To find \( R \), we need to solve for \( R^2 \):
\[
R^2 = \frac{3}{\pi}
\]
Then, we take the square root of both sides:
\[
R = \sqrt{\frac{3}{\pi}}
\]
Now, we can substitute \( R \) and \( h \) into the surface area formula.
First, let's calculate \( R \):
\[
R \approx \sqrt{\frac{3}{3.14159}} \approx \sqrt{0.95493} \approx 0.977
\]
Now, using \( R \approx 0.977 \, \text{ft} \) and \( h = 2 \, \text{ft} \):
Now, we compute the total surface area \( S \):
\[
S = 2\pi R h + 2\pi R^2
\]
Calculating each part:
1. **Lateral surface area**:
\[
2\pi R h = 2\pi (0.977)(2) \approx 2\pi (1.954) \approx 12.26 \, \text{ft}^2
\]
2. **Area of the two bases**:
\[
2\pi R^2 = 2\pi \left(\frac{3}{\pi}\right) = 2 \cdot 3 = 6 \, \text{ft}^2
\]
Adding both components together:
\[
S \approx 12.26 + 6 = 18.26 \, \text{ft}^2
\]
Thus, the total surface area of the cylinder, rounded to the nearest hundredth, is:
\[
\boxed{18.26 \, \text{ft}^2}
\]
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