To determine whether the triangles ΔPRQ and ΔFGH are similar, we analyze the given angles:
-
For ΔPRQ:
- ∠P = 30°
- ∠R = 127°
To find ∠Q: \[ ∠Q = 180° - (∠P + ∠R) = 180° - (30° + 127°) = 180° - 157° = 23° \]
-
For ΔFGH:
- ∠H = 30°
- ∠G = 23°
To find ∠F: \[ ∠F = 180° - (∠H + ∠G) = 180° - (30° + 23°) = 180° - 53° = 127° \]
Now we have the angles for both triangles:
- For ΔPRQ: ∠P = 30°, ∠R = 127°, ∠Q = 23°
- For ΔFGH: ∠F = 127°, ∠G = 23°, ∠H = 30°
We can see that:
- ∠P = ∠H = 30°
- ∠Q = ∠G = 23°
- ∠R = ∠F = 127°
Since all three angles in ΔPRQ correspond to the angles in ΔFGH, the criterion satisfied here is AA (Angle-Angle) similarity.
Thus, the answer is AA.