Question
Find the volume of these 2 cylinders
1. Hight 8 base 3
2.hight 4 base 6
1. Hight 8 base 3
2.hight 4 base 6
Answers
GPT-4o mini
To find the volume of a cylinder, you can use the formula:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cylinder.
The base given in your problem is the diameter. To find the radius, simply divide the diameter by 2.
### Cylinder 1:
- Height \( h_1 = 8 \)
- Diameter (base) \( d_1 = 3 \)
- Radius \( r_1 = \frac{d_1}{2} = \frac{3}{2} = 1.5 \)
Now, plug in the values into the volume formula:
\[
V_1 = \pi (1.5)^2 (8) = \pi (2.25) (8) = 18\pi
\]
### Cylinder 2:
- Height \( h_2 = 4 \)
- Diameter (base) \( d_2 = 6 \)
- Radius \( r_2 = \frac{d_2}{2} = \frac{6}{2} = 3 \)
Now, plug in the values into the volume formula:
\[
V_2 = \pi (3)^2 (4) = \pi (9) (4) = 36\pi
\]
### Summary:
- Volume of Cylinder 1: \( 18\pi \)
- Volume of Cylinder 2: \( 36\pi \)
If you would like numerical approximations, you can calculate these using \( \pi \approx 3.14 \):
- Volume of Cylinder 1: \( 18 \times 3.14 \approx 56.52 \)
- Volume of Cylinder 2: \( 36 \times 3.14 \approx 113.04 \)
Thus, the volumes are:
- Cylinder 1: \( 18\pi \) (approximately \( 56.52 \))
- Cylinder 2: \( 36\pi \) (approximately \( 113.04 \))
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cylinder.
The base given in your problem is the diameter. To find the radius, simply divide the diameter by 2.
### Cylinder 1:
- Height \( h_1 = 8 \)
- Diameter (base) \( d_1 = 3 \)
- Radius \( r_1 = \frac{d_1}{2} = \frac{3}{2} = 1.5 \)
Now, plug in the values into the volume formula:
\[
V_1 = \pi (1.5)^2 (8) = \pi (2.25) (8) = 18\pi
\]
### Cylinder 2:
- Height \( h_2 = 4 \)
- Diameter (base) \( d_2 = 6 \)
- Radius \( r_2 = \frac{d_2}{2} = \frac{6}{2} = 3 \)
Now, plug in the values into the volume formula:
\[
V_2 = \pi (3)^2 (4) = \pi (9) (4) = 36\pi
\]
### Summary:
- Volume of Cylinder 1: \( 18\pi \)
- Volume of Cylinder 2: \( 36\pi \)
If you would like numerical approximations, you can calculate these using \( \pi \approx 3.14 \):
- Volume of Cylinder 1: \( 18 \times 3.14 \approx 56.52 \)
- Volume of Cylinder 2: \( 36 \times 3.14 \approx 113.04 \)
Thus, the volumes are:
- Cylinder 1: \( 18\pi \) (approximately \( 56.52 \))
- Cylinder 2: \( 36\pi \) (approximately \( 113.04 \))