Find the product. Simplify your answer.

Question

6(4z2+2z+1)

Answer 1

To find the product of \( 6(4z^2 + 2z + 1) \), you need to distribute the \( 6 \) to each term inside the parentheses.

Starting with the expression:

\[ 6(4z^2 + 2z + 1) \]

Distributing \( 6 \):

1. \( 6 \times 4z^2 = 24z^2 \)
2. \( 6 \times 2z = 12z \)
3. \( 6 \times 1 = 6 \)

Now, combine all the results:

\[ 24z^2 + 12z + 6 \]

Thus, the simplified product is:

\[ \boxed{24z^2 + 12z + 6} \]