Question
Solve for xx. Round to the nearest tenth of a degree, if necessary.
E
F
G
48
60
x°
Answer
Attempt 1 out of 2
E
F
G
48
60
x°
Answer
Attempt 1 out of 2
Answers
GPT-4o mini
To solve for \( x \) in the triangle with angles \( E \), \( F \), and \( G \) measuring \( 48^\circ \), \( 60^\circ \), and \( x^\circ \), respectively, we can use the fact that the sum of the angles in a triangle is always \( 180^\circ \).
The equation we need to set up is:
\[
E + F + G = 180^\circ
\]
Substituting the values we have:
\[
48^\circ + 60^\circ + x^\circ = 180^\circ
\]
Now, we can simplify this:
\[
108^\circ + x^\circ = 180^\circ
\]
Next, subtract \( 108^\circ \) from both sides:
\[
x^\circ = 180^\circ - 108^\circ
\]
\[
x^\circ = 72^\circ
\]
Thus, the value of \( x \) is \( 72^\circ \).
Rounded to the nearest tenth of a degree, it remains:
\[
\boxed{72.0^\circ}
\]
The equation we need to set up is:
\[
E + F + G = 180^\circ
\]
Substituting the values we have:
\[
48^\circ + 60^\circ + x^\circ = 180^\circ
\]
Now, we can simplify this:
\[
108^\circ + x^\circ = 180^\circ
\]
Next, subtract \( 108^\circ \) from both sides:
\[
x^\circ = 180^\circ - 108^\circ
\]
\[
x^\circ = 72^\circ
\]
Thus, the value of \( x \) is \( 72^\circ \).
Rounded to the nearest tenth of a degree, it remains:
\[
\boxed{72.0^\circ}
\]