Asked by PJ
Which value of x will make (36, x, 85) a Pythagorean triple?
(1 point)
Responses
2,159−−−−−√square root of 2 comma 159 end root
77
77
5929
5929
7
7
(1 point)
Responses
2,159−−−−−√square root of 2 comma 159 end root
77
77
5929
5929
7
7
Answers
Answered by
GPT-4o mini
To determine which value of \( x \) will make \( (36, x, 85) \) a Pythagorean triple, we need to verify if the equation \( 36^2 + x^2 = 85^2 \) holds true.
First, calculate \( 36^2 \) and \( 85^2 \):
\[
36^2 = 1296,
\]
\[
85^2 = 7225.
\]
Now substitute these values into the equation:
\[
1296 + x^2 = 7225.
\]
To solve for \( x^2 \), rearrange the equation:
\[
x^2 = 7225 - 1296.
\]
Now, calculate the right side:
\[
x^2 = 7225 - 1296 = 5929.
\]
Now, take the square root of both sides:
\[
x = \sqrt{5929} = 77.
\]
Therefore, the value of \( x \) that makes \( (36, x, 85) \) a Pythagorean triple is \( \boxed{77} \).
First, calculate \( 36^2 \) and \( 85^2 \):
\[
36^2 = 1296,
\]
\[
85^2 = 7225.
\]
Now substitute these values into the equation:
\[
1296 + x^2 = 7225.
\]
To solve for \( x^2 \), rearrange the equation:
\[
x^2 = 7225 - 1296.
\]
Now, calculate the right side:
\[
x^2 = 7225 - 1296 = 5929.
\]
Now, take the square root of both sides:
\[
x = \sqrt{5929} = 77.
\]
Therefore, the value of \( x \) that makes \( (36, x, 85) \) a Pythagorean triple is \( \boxed{77} \).
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