Which value of x will make (36, x, 85) a Pythagorean triple?

(1 point)
Responses

2,159−−−−−√square root of 2 comma 159 end root

77
77

5929
5929

7
7

1 answer

To determine which value of \( x \) will make \( (36, x, 85) \) a Pythagorean triple, we need to verify if the equation \( 36^2 + x^2 = 85^2 \) holds true.

First, calculate \( 36^2 \) and \( 85^2 \):

\[ 36^2 = 1296, \] \[ 85^2 = 7225. \]

Now substitute these values into the equation:

\[ 1296 + x^2 = 7225. \]

To solve for \( x^2 \), rearrange the equation:

\[ x^2 = 7225 - 1296. \]

Now, calculate the right side:

\[ x^2 = 7225 - 1296 = 5929. \]

Now, take the square root of both sides:

\[ x = \sqrt{5929} = 77. \]

Therefore, the value of \( x \) that makes \( (36, x, 85) \) a Pythagorean triple is \( \boxed{77} \).