Question
What number of triangles can be formed using the set of three side lengths 11in,15in,6in
One unquie triangle
Many triangles
No triangles
One unquie triangle
Many triangles
No triangles
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine whether a triangle can be formed with the side lengths of 11 inches, 15 inches, and 6 inches, we can apply the triangle inequality theorem. This theorem states that for any triangle with side lengths \( a \), \( b \), and \( c \) (where \( a \leq b \leq c \)), the following conditions must hold:
1. \( a + b > c \)
2. \( a + c > b \)
3. \( b + c > a \)
Let's analyze the given side lengths: \( a = 6 \), \( b = 11 \), and \( c = 15 \).
1. Check \( a + b > c \):
\[
6 + 11 = 17 > 15 \quad \text{(True)}
\]
2. Check \( a + c > b \):
\[
6 + 15 = 21 > 11 \quad \text{(True)}
\]
3. Check \( b + c > a \):
\[
11 + 15 = 26 > 6 \quad \text{(True)}
\]
All three conditions of the triangle inequality are satisfied. Therefore, a triangle can indeed be formed with the side lengths of 11 inches, 15 inches, and 6 inches.
Since the side lengths are fixed, only **one unique triangle** can be formed with these dimensions.
So, the answer is: **One unique triangle**.
1. \( a + b > c \)
2. \( a + c > b \)
3. \( b + c > a \)
Let's analyze the given side lengths: \( a = 6 \), \( b = 11 \), and \( c = 15 \).
1. Check \( a + b > c \):
\[
6 + 11 = 17 > 15 \quad \text{(True)}
\]
2. Check \( a + c > b \):
\[
6 + 15 = 21 > 11 \quad \text{(True)}
\]
3. Check \( b + c > a \):
\[
11 + 15 = 26 > 6 \quad \text{(True)}
\]
All three conditions of the triangle inequality are satisfied. Therefore, a triangle can indeed be formed with the side lengths of 11 inches, 15 inches, and 6 inches.
Since the side lengths are fixed, only **one unique triangle** can be formed with these dimensions.
So, the answer is: **One unique triangle**.
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