Question

A simple electric circuit has the following properties:

resistance: 12 ohms
voltage: 96 V
Which circuit below has the same current?

(1 point)

A. resistance: 12 ohms voltage: 24 V

B. resistance: 8 ohms voltage: 108 V

C. resistance: 4 ohms voltage: 96 V

D. resistance: 6 ohms voltage: 48 V

Answer 1

To find out which circuit has the same current, we can use Ohm's Law, which states that:

\[ I = \frac{V}{R} \]

where:
- \( I \) is the current,
- \( V \) is the voltage, and
- \( R \) is the resistance.

First, let's calculate the current for the given parameters:

Given:
- Resistance \( R = 12 \) ohms
- Voltage \( V = 96 \) V

Using Ohm's Law:

\[
I = \frac{96 \, \text{V}}{12 \, \text{ohms}} = 8 \, \text{A}
\]

Now we need to calculate the current for each of the options:

**A.**
- Resistance: 12 ohms
- Voltage: 24 V

\[
I = \frac{24 \, \text{V}}{12 \, \text{ohms}} = 2 \, \text{A}
\]

**B.**
- Resistance: 8 ohms
- Voltage: 108 V

\[
I = \frac{108 \, \text{V}}{8 \, \text{ohms}} = 13.5 \, \text{A}
\]

**C.**
- Resistance: 4 ohms
- Voltage: 96 V

\[
I = \frac{96 \, \text{V}}{4 \, \text{ohms}} = 24 \, \text{A}
\]

**D.**
- Resistance: 6 ohms
- Voltage: 48 V

\[
I = \frac{48 \, \text{V}}{6 \, \text{ohms}} = 8 \, \text{A}
\]

Now let's summarize the currents calculated:

- Current for A: 2 A
- Current for B: 13.5 A
- Current for C: 24 A
- Current for D: 8 A

The circuit that has the same current (8 A) as the original circuit is:

**D. resistance: 6 ohms voltage: 48 V**