To find out which circuit has the same current, we can use Ohm's Law, which states that:
\[ I = \frac{V}{R} \]
where:
- \( I \) is the current,
- \( V \) is the voltage, and
- \( R \) is the resistance.
First, let's calculate the current for the given parameters:
Given:
- Resistance \( R = 12 \) ohms
- Voltage \( V = 96 \) V
Using Ohm's Law:
\[ I = \frac{96 , \text{V}}{12 , \text{ohms}} = 8 , \text{A} \]
Now we need to calculate the current for each of the options:
A.
- Resistance: 12 ohms
- Voltage: 24 V
\[ I = \frac{24 , \text{V}}{12 , \text{ohms}} = 2 , \text{A} \]
B.
- Resistance: 8 ohms
- Voltage: 108 V
\[ I = \frac{108 , \text{V}}{8 , \text{ohms}} = 13.5 , \text{A} \]
C.
- Resistance: 4 ohms
- Voltage: 96 V
\[ I = \frac{96 , \text{V}}{4 , \text{ohms}} = 24 , \text{A} \]
D.
- Resistance: 6 ohms
- Voltage: 48 V
\[ I = \frac{48 , \text{V}}{6 , \text{ohms}} = 8 , \text{A} \]
Now let's summarize the currents calculated:
- Current for A: 2 A
- Current for B: 13.5 A
- Current for C: 24 A
- Current for D: 8 A
The circuit that has the same current (8 A) as the original circuit is:
D. resistance: 6 ohms voltage: 48 V
2 answers