Asked by Sara
Solve for [0, 360)
2sinxcosx + cosx =0
2sinxcosx = -cosx
2sinx = -cosx/cosx
sinx = -1/2
{210, 330)
Is this correct?
2sinxcosx + cosx =0
2sinxcosx = -cosx
2sinx = -cosx/cosx
sinx = -1/2
{210, 330)
Is this correct?
Answers
Answered by
Reiny
no , you only have half the answers
2sinxcosx + cosx =0
cosx(2sinx + 1) = 0
cosx = 0 or sinx = -1/2
if cosx = 0, x = 90° , 270°
if sinx = -1/2, x = 210°, 330°
(you only had the last case)
2sinxcosx + cosx =0
cosx(2sinx + 1) = 0
cosx = 0 or sinx = -1/2
if cosx = 0, x = 90° , 270°
if sinx = -1/2, x = 210°, 330°
(you only had the last case)
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