Asked by Anonymous
2^6x-1 = 9
and...
can you solve exponential functions without using log if the base isn't the same..?
and...
can you solve exponential functions without using log if the base isn't the same..?
Answers
Answered by
Reiny
log(2^(6x-1))=log9, (assuming your exponent is 6x-1)
(6x-1)log2=log9
6x-1=log9/log2
etc
Unless you use some kind of interpolation, using logs along with a calculator will give you the most accurate answer.
(I got x=.6949875)
(6x-1)log2=log9
6x-1=log9/log2
etc
Unless you use some kind of interpolation, using logs along with a calculator will give you the most accurate answer.
(I got x=.6949875)
Answered by
atianna
you got 8 hours of sleep on Monday night and 7 hours of sleep on tuesday night. On wednesday, you got 4 hours of sleep because you were up late working on a english paper. On thursday and friday you got 9 hours of sleep each night to make up for wednseday. Use a verbal model to find how many hours of sleep you got during the week?
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