Question

The Midpoint Formula Quick Check
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LUSSON 4
J
a
K
-6-5-4-3-2-1
2 3 45
Does adding 7+2 and then dividing by 2 help you find the find midpoint of line segment JK?
(1 point)
Yes because (7+2) 2 calculates the average, or midpoint, of the x-coordinates of points Jana K
No because (7,2) not the coordinate of point or
No because 7 should be added to 3, then multiplied by 2 in find the midpoint
Yas because (72) 2tes the average, or mistpoost, of the y-coordinates of points Jant K
Next

Answer 1

To find the midpoint of a line segment defined by two points \( J(x_1, y_1) \) and \( K(x_2, y_2) \), you can use the Midpoint Formula:

\[
M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

From your question, it seems you are asking whether adding \( 7 + 2 \) and then dividing by \( 2 \) helps find the midpoint of line segment \( JK \).

If \( 7 \) and \( 2 \) correspond to the y-coordinates of points \( J \) and \( K \), then:

\[
\frac{7 + 2}{2} = \frac{9}{2} = 4.5
\]

This calculation will give you the average (or midpoint) of the y-coordinates of points \( J \) and \( K \).

The options you presented mostly address the understanding of the values at play:

1. **Yes because (7+2) / 2 calculates the average, or midpoint, of the y-coordinates of points J and K** - this option seems correct if \( 7 \) and \( 2 \) are indeed the y-coordinates.

2. **No because (7,2) not the coordinate of point J or K** - this option doesn't matter here as the previous one is correct based on calculations.

3. **No because 7 should be added to 3, then multiplied by 2 in find the midpoint** - it appears to misunderstand the midpoint formula as it involves averaging and not simply multiplying.

4. **Yes because (7,2) / 2 gives the average, or midpoint, of the y-coordinates of points J and K** - this option is also very close, but it’s written incorrectly as averages aren't found by dividing coordinates as pairs.

Considering the context, the correct answer would be the first option, assuming \( 7 \) and \( 2 \) are indeed y-coordinates.