Question

Chemical solution C is made by mixing chemical A and chemical B in the ratio of 5 to 3. How many beakers of chemical A and chemical B are needed to make 16 beakers of chemical solution C?


A.
12 beakers of chemical A, 4 beakers of chemical B
B.
6 beakers of chemical A, 10 beakers of chemical B
C.
14 beakers of chemical A, 2 beakers of chemical B
D.
10 beakers of chemical A, 6 beakers of chemical B
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Answer 1

To find out how many beakers of chemical A and chemical B are needed to make 16 beakers of chemical solution C, we need to reference the mixing ratio of chemical A to chemical B, which is 5:3.

This means that for every 5 parts of chemical A, there are 3 parts of chemical B. The total parts in the mixture is:

\(5 + 3 = 8\) parts.

Now, to find out how many beakers correspond to chemical A and chemical B in solution C, we can calculate the number of beakers of each chemical based on the total volume of 16 beakers of solution C.

1. **Calculate the amount of chemical A**:
\[
\text{Beakers of chemical A} = \frac{5}{8} \times 16 = 10 \text{ beakers}
\]

2. **Calculate the amount of chemical B**:
\[
\text{Beakers of chemical B} = \frac{3}{8} \times 16 = 6 \text{ beakers}
\]

Thus, to make 16 beakers of solution C, you need 10 beakers of chemical A and 6 beakers of chemical B.

The correct answer is:

**D. 10 beakers of chemical A, 6 beakers of chemical B**.