Marcus solved for x in the quadratic equation x2 – 10x + 25 = 0.

x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction
x = StartFraction negative (10) plus or minus StartRoot (10) squared + 4 (1)(25) EndRoot Over 2(1) EndFraction
x = StartFraction negative 10 plus or minus StartRoot 200 EndRoot Over 2 EndFraction
What is true about Marcus’s work? Check all that apply.

Marcus should have substituted –10 for b, not 10.
The denominator should be 1, not 2.
Marcus should have subtracted 4(1)(25) in the square root.
This equation, when solved correctly, only has 1 real number solution.
This equation has 2 real number solutions.

1 answer

Let's analyze Marcus's work step-by-step and identify what is true about it.

The equation Marcus worked with is: \[ x^2 - 10x + 25 = 0. \]

  1. The correct coefficients for the quadratic formula \(-b \pm \sqrt{b^2 - 4ac} / 2a\) are:
    • \(a = 1\)
    • \(b = -10\) (Note that in the equation, the coefficient of \(x\) is \(-10\), not \(10\).)
    • \(c = 25\)

Analyzing the options:

  1. Marcus should have substituted –10 for b, not 10.
    True. He mistakenly used \(10\) instead of \(-10\).

  2. The denominator should be 1, not 2.
    False. The correct denominator is \(2a\) which is \(2 \times 1 = 2\).

  3. Marcus should have subtracted 4(1)(25) in the square root.
    False. The correct calculation inside the square root should be \(b^2 - 4ac\) which is \( (-10)^2 - 4(1)(25) \). So it should be \(100 - 100 = 0\).

  4. This equation, when solved correctly, only has 1 real number solution.
    True. Since the discriminant \(b^2 - 4ac = 0\), there is 1 real solution (a double root).

  5. This equation has 2 real number solutions.
    False. As established earlier, the discrimination is zero, indicating only one real number solution.

In summary, the statements that are true concerning Marcus's work are:

  • Marcus should have substituted –10 for b, not 10.
  • This equation, when solved correctly, only has 1 real number solution.