3(6b-1)-7(2b+3)=0

Answer 1

To solve the equation \(3(6b-1) - 7(2b+3) = 0\), we'll start by distributing the terms:

1. Distribute \(3\) in the first term: \[ 3(6b) - 3(1) = 18b - 3 \]

2. Distribute \(-7\) in the second term: \[ -7(2b) - 7(3) = -14b - 21 \]

Now, substitute these back into the equation: \[ 18b - 3 - 14b - 21 = 0 \]

Next, combine like terms: \[ (18b - 14b) + (-3 - 21) = 0 \] \[ 4b - 24 = 0 \]

Now, isolate \(b\) by adding \(24\) to both sides: \[ 4b = 24 \]

Now, divide both sides by \(4\): \[ b = 6 \]

Thus, the solution is: \[ \boxed{6} \]