Question
On a number line, the irrational number x to the power of 2+6
lies between which two whole numbers?
between 12 and 13
between 15 and 16
between 59 and 60
between 83 and 84
lies between which two whole numbers?
between 12 and 13
between 15 and 16
between 59 and 60
between 83 and 84
Answers
Answered by
GPT-4o mini
To determine the range in which \(x\) can lie such that \(x^2 + 6\) falls between the specified whole numbers, we will solve the inequalities for \(x^2\).
1. **Between 12 and 13**:
\[
12 < x^2 + 6 < 13
\]
Subtracting 6 from all parts gives:
\[
6 < x^2 < 7
\]
Taking the square root:
\[
\sqrt{6} < |x| < \sqrt{7}
\]
2. **Between 15 and 16**:
\[
15 < x^2 + 6 < 16
\]
Subtracting 6:
\[
9 < x^2 < 10
\]
Taking the square root:
\[
3 < |x| < \sqrt{10}
\]
3. **Between 59 and 60**:
\[
59 < x^2 + 6 < 60
\]
Subtracting 6:
\[
53 < x^2 < 54
\]
Taking the square root:
\[
\sqrt{53} < |x| < \sqrt{54}
\]
4. **Between 83 and 84**:
\[
83 < x^2 + 6 < 84
\]
Subtracting 6:
\[
77 < x^2 < 78
\]
Taking the square root:
\[
\sqrt{77} < |x| < \sqrt{78}
\]
Now let's check the approximations of the square roots to determine which intervals correspond to irrational numbers:
- \(\sqrt{6} \approx 2.45\), \(\sqrt{7} \approx 2.65\) → Interval between \(2.45\) and \(2.65\).
- \(\sqrt{9} = 3\), \(\sqrt{10} \approx 3.16\) → Interval between \(3\) and \(3.16\).
- \(\sqrt{53} \approx 7.28\), \(\sqrt{54} \approx 7.35\) → Interval between \(7.28\) and \(7.35\).
- \(\sqrt{77} \approx 8.77\), \(\sqrt{78} \approx 8.83\) → Interval between \(8.77\) and \(8.83\).
### Conclusion
Now we established that:
- For \(x^2 + 6\) being between 12 and 13, \(x\) lies between approximately \(2.45\) and \(2.65\).
- For the other options, similar calculations can be applied.
Thus, the irrational number \(x^2 + 6\) does not fit between 12 and 13 for rational \(x\), meaning approximate values yield the function as predominantly becoming irrational.
However, the expression indicates that \(x^2 + 6\) achieves proximity towards ratio-defined values aligning with specific whole numbers. The arrangement confirms locations.
The intervals imply:
- Between \(83\) and \(84\): The number nearest to a whole number hence fits.
The answer thus confirms:
- The value \(x^2 + 6\) lies best **between 83 and 84**.
1. **Between 12 and 13**:
\[
12 < x^2 + 6 < 13
\]
Subtracting 6 from all parts gives:
\[
6 < x^2 < 7
\]
Taking the square root:
\[
\sqrt{6} < |x| < \sqrt{7}
\]
2. **Between 15 and 16**:
\[
15 < x^2 + 6 < 16
\]
Subtracting 6:
\[
9 < x^2 < 10
\]
Taking the square root:
\[
3 < |x| < \sqrt{10}
\]
3. **Between 59 and 60**:
\[
59 < x^2 + 6 < 60
\]
Subtracting 6:
\[
53 < x^2 < 54
\]
Taking the square root:
\[
\sqrt{53} < |x| < \sqrt{54}
\]
4. **Between 83 and 84**:
\[
83 < x^2 + 6 < 84
\]
Subtracting 6:
\[
77 < x^2 < 78
\]
Taking the square root:
\[
\sqrt{77} < |x| < \sqrt{78}
\]
Now let's check the approximations of the square roots to determine which intervals correspond to irrational numbers:
- \(\sqrt{6} \approx 2.45\), \(\sqrt{7} \approx 2.65\) → Interval between \(2.45\) and \(2.65\).
- \(\sqrt{9} = 3\), \(\sqrt{10} \approx 3.16\) → Interval between \(3\) and \(3.16\).
- \(\sqrt{53} \approx 7.28\), \(\sqrt{54} \approx 7.35\) → Interval between \(7.28\) and \(7.35\).
- \(\sqrt{77} \approx 8.77\), \(\sqrt{78} \approx 8.83\) → Interval between \(8.77\) and \(8.83\).
### Conclusion
Now we established that:
- For \(x^2 + 6\) being between 12 and 13, \(x\) lies between approximately \(2.45\) and \(2.65\).
- For the other options, similar calculations can be applied.
Thus, the irrational number \(x^2 + 6\) does not fit between 12 and 13 for rational \(x\), meaning approximate values yield the function as predominantly becoming irrational.
However, the expression indicates that \(x^2 + 6\) achieves proximity towards ratio-defined values aligning with specific whole numbers. The arrangement confirms locations.
The intervals imply:
- Between \(83\) and \(84\): The number nearest to a whole number hence fits.
The answer thus confirms:
- The value \(x^2 + 6\) lies best **between 83 and 84**.
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