Asked by pp

Factor out the CGF
3, x, squared, y, plus, 15, x, y, minus, 21, x, y, squared3x
2
y+15xy−21xy
2

Answer
Attempt 1 out of 2
Multiple Choice Answers
3, x, left parenthesis, x, y, plus, 5, y, minus, 7, y, right parenthesis3x(xy+5y−7y)
3, x, y, left parenthesis, x, plus, 5, minus, 7, y, right parenthesis3xy(x+5−7y)
3, x, left parenthesis, x, y, plus, 5, y, minus, 7, y, squared, right parenthesis3x(xy+5y−7y
2
)
3, x, y, left parenthesis, 1, plus, 5, minus, 7, y, right parenthesis3xy(1+5−7y)

Answers

Answered by GPT-4o mini
To factor the expression \(3x^2y + 15xy - 21xy^2\), we first look for the greatest common factor (GCF) of the coefficients and variables in the terms.

1. **Identify the GCF:**
- The coefficients are \(3\), \(15\), and \(-21\). The GCF of these numbers is \(3\).
- The variable part consists of \(x^2y\), \(xy\), and \(-21xy^2\). The GCF for the variable part is \(xy\), as all terms have at least one \(x\) and one \(y\).

Thus, the overall GCF is \(3xy\).

2. **Factor out the GCF:**
Now we divide each term in the expression by the GCF \(3xy\):
\[
\frac{3x^2y}{3xy} + \frac{15xy}{3xy} - \frac{21xy^2}{3xy} = x + 5 - 7y
\]

Therefore, we can rewrite the expression as:
\[
3xy(x + 5 - 7y)
\]

3. **Conclusion:**
The factored form of the expression \(3x^2y + 15xy - 21xy^2\) is:
\[
3xy(x + 5 - 7y)
\]

Among the provided answer choices, this corresponds to:
- \(3xy(x + 5 - 7y)\) or it's equivalent.

However, this doesn’t seem to appear directly in the answer choices given. Let’s double-check the corresponding choice:

- The closest choice would be **\(3x\left(xy + 5y - 7y^2\right)\)** which results by grouping differently and factoring the coefficients accordingly, taking care of terms.

Thus, the correct interpretation of the multiple-choice may point to:
\[
3x\left(xy + 5y - 7y^2\right)
\]

This matches up with looking for \(3xy\)’s common factors.

Final answer:
**\(3xy(x + 5 - 7y)\)** or is shown as **\(3x\left(xy + 5y - 7y^2\right)\)**.

Related Questions