Question

Question
In which situation did the car achieve the greatest efficiency? (Assume the cars all have the same mass.)(1 point)
Responses

a car that traveled 80 kilometers on 5.0 liters of gas
a car that traveled 80 kilometers on 5.0 liters of gas

a car that traveled 70 kilometers on 5.0 liters of gas
a car that traveled 70 kilometers on 5.0 liters of gas

a car that traveled 50 kilometers on 4.0 liters of gas
a car that traveled 50 kilometers on 4.0 liters of gas

a car that traveled 90 kilometers on 6.0 liters of gas

Answer 1

To determine which car achieved the greatest fuel efficiency, we need to calculate the fuel efficiency (in kilometers per liter) for each car. The formula for fuel efficiency is:

\[
\text{Fuel Efficiency} = \frac{\text{Distance Traveled (km)}}{\text{Liters of Gas Used}}
\]

Let's calculate the efficiency for each car:

1. **Car 1:** Traveled 80 km on 5.0 liters
\[
\text{Efficiency} = \frac{80 \text{ km}}{5.0 \text{ L}} = 16 \text{ km/L}
\]

2. **Car 2:** Traveled 70 km on 5.0 liters
\[
\text{Efficiency} = \frac{70 \text{ km}}{5.0 \text{ L}} = 14 \text{ km/L}
\]

3. **Car 3:** Traveled 50 km on 4.0 liters
\[
\text{Efficiency} = \frac{50 \text{ km}}{4.0 \text{ L}} = 12.5 \text{ km/L}
\]

4. **Car 4:** Traveled 90 km on 6.0 liters
\[
\text{Efficiency} = \frac{90 \text{ km}}{6.0 \text{ L}} = 15 \text{ km/L}
\]

Now we can summarize the efficiencies:
- Car 1: 16 km/L
- Car 2: 14 km/L
- Car 3: 12.5 km/L
- Car 4: 15 km/L

The car that achieved the greatest efficiency is **Car 1**, which traveled **80 kilometers on 5.0 liters of gas**, resulting in **16 km/L**.