Question

The formula for surface area of a cube is A=6s2 , where A is area of the square and s is the length of an edge of the cube. What is this formula solved for s in terms of A? (1 point) Responses s=A6 s is equal to cap A over 6 s=6A√6 s is equal to the fraction with numerator square root of 6 cap A and denominator 6 s=6A−−−√ s is equal to square root of 6 cap A s=6A

Answer 1

To solve the formula for surface area of a cube \( A = 6s^2 \) for \( s \) in terms of \( A \), we can follow these steps:

1. Start with the formula:
\[
A = 6s^2
\]

2. Divide both sides by 6:
\[
\frac{A}{6} = s^2
\]

3. Take the square root of both sides:
\[
s = \sqrt{\frac{A}{6}}
\]

In the options provided, the correct response corresponding to this solution for \( s \) in terms of \( A \) is:
\[
s = \frac{\sqrt{A}}{\sqrt{6}} \text{ or } s = \sqrt{\frac{A}{6}}
\]

However, such representation might not be explicitly listed in your options. If we consider the square root of \( A \) and provide it in the form of fractions to satisfy the choices available:

It seems that none of the options presented is exactly correct, but we can infer that \( s = \sqrt{\frac{A}{6}} \) follows directly based on manipulation from the original equation. This aligns with the process of solving for \( s \) while respecting the mathematical conventions of isolating for a variable.

Thus, none of the listed responses you provided seem to accurately reflect the transformation of the equation; instead, the correct representation should be:
\[
s = \sqrt{\frac{A}{6}} \text{ or } s = \frac{\sqrt{A}}{\sqrt{6}}
\]