Question
Describe the volume of the cylinder with a base radius of 2.5 in.
and a height of 9 in. (1 point)
(2.5)(9)in.
3
π(9) (2.5)in
2
.
3
π(2.5) (9)in
2
.
3
π (2.5)(9)in.
3
and a height of 9 in. (1 point)
(2.5)(9)in.
3
π(9) (2.5)in
2
.
3
π(2.5) (9)in
2
.
3
π (2.5)(9)in.
3
Answers
GPT-4o mini
To calculate the volume of a cylinder, you can use the formula:
\[
V = \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius of the base, and \( h \) is the height.
In this case, the base radius \( r \) is 2.5 inches and the height \( h \) is 9 inches. Plugging in these values into the formula:
\[
V = \pi (2.5)^2 (9)
\]
Calculating \( (2.5)^2 \):
\[
(2.5)^2 = 6.25
\]
Now substitute back into the volume formula:
\[
V = \pi (6.25) (9)
\]
Now, multiply \( 6.25 \) by \( 9 \):
\[
6.25 \times 9 = 56.25
\]
So the volume is:
\[
V = 56.25\pi \, \text{in}^3
\]
Thus, the volume of the cylinder is:
\[
56.25\pi \, \text{in}^3
\]
It can be approximated numerically as \( 176.71 \, \text{in}^3 \) if you consider \( \pi \approx 3.14 \).
\[
V = \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius of the base, and \( h \) is the height.
In this case, the base radius \( r \) is 2.5 inches and the height \( h \) is 9 inches. Plugging in these values into the formula:
\[
V = \pi (2.5)^2 (9)
\]
Calculating \( (2.5)^2 \):
\[
(2.5)^2 = 6.25
\]
Now substitute back into the volume formula:
\[
V = \pi (6.25) (9)
\]
Now, multiply \( 6.25 \) by \( 9 \):
\[
6.25 \times 9 = 56.25
\]
So the volume is:
\[
V = 56.25\pi \, \text{in}^3
\]
Thus, the volume of the cylinder is:
\[
56.25\pi \, \text{in}^3
\]
It can be approximated numerically as \( 176.71 \, \text{in}^3 \) if you consider \( \pi \approx 3.14 \).