To determine which function has a y-intercept, we need to find the value of each function when \( x = 0 \).
-
For \( f(x) = \sqrt{x - 2} \):
- Substitute \( x = 0 \): \[ f(0) = \sqrt{0 - 2} = \sqrt{-2} \] Since the square root of a negative number is not real, \( f(0) \) is not defined. Thus, \( f(x) \) has no y-intercept.
-
For \( g(x) = \sqrt{2 - x} \):
- Substitute \( x = 0 \): \[ g(0) = \sqrt{2 - 0} = \sqrt{2} \] This is a real number, so \( g(x) \) has a y-intercept.
From the analysis above, only \( g(x) \) has a y-intercept.
The correct option is: Option 2: g(x).