Question
volume of the cone with radius of 6 and height of 15, use 3.14 for pie
Answers
GPT-4o mini
To calculate the volume of a cone, you can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14.
Given:
- \( r = 6 \)
- \( h = 15 \)
Plugging these values into the formula:
\[
V = \frac{1}{3} \times 3.14 \times (6^2) \times 15
\]
Calculating \( 6^2 \):
\[
6^2 = 36
\]
Now substitute this value back into the equation:
\[
V = \frac{1}{3} \times 3.14 \times 36 \times 15
\]
Now calculate \( 36 \times 15 \):
\[
36 \times 15 = 540
\]
So the equation now looks like this:
\[
V = \frac{1}{3} \times 3.14 \times 540
\]
Now calculate \( 3.14 \times 540 \):
\[
3.14 \times 540 = 1695.6
\]
Finally, divide by 3:
\[
V = \frac{1695.6}{3} = 565.2
\]
Therefore, the volume of the cone is **565.2 cubic units**.
\[
V = \frac{1}{3} \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14.
Given:
- \( r = 6 \)
- \( h = 15 \)
Plugging these values into the formula:
\[
V = \frac{1}{3} \times 3.14 \times (6^2) \times 15
\]
Calculating \( 6^2 \):
\[
6^2 = 36
\]
Now substitute this value back into the equation:
\[
V = \frac{1}{3} \times 3.14 \times 36 \times 15
\]
Now calculate \( 36 \times 15 \):
\[
36 \times 15 = 540
\]
So the equation now looks like this:
\[
V = \frac{1}{3} \times 3.14 \times 540
\]
Now calculate \( 3.14 \times 540 \):
\[
3.14 \times 540 = 1695.6
\]
Finally, divide by 3:
\[
V = \frac{1695.6}{3} = 565.2
\]
Therefore, the volume of the cone is **565.2 cubic units**.