To determine the gravitational force of the robotic helicopter on Mars, we can use the ratio of gravitational accelerations on Mars and Earth. The gravitational force \( F \) can be calculated using the formula:
\[ F = m \cdot g \]
Where \( m \) is the mass of the helicopter and \( g \) is the acceleration due to gravity.
Given that on Earth the gravitational force \( F_{\text{Earth}} = 17.65 , \text{N} \) and \( g_{\text{Earth}} = 9.8 , \text{m/s}^2 \), we can find the mass \( m \) of the helicopter:
\[ m = \frac{F_{\text{Earth}}}{g_{\text{Earth}}} = \frac{17.65 , \text{N}}{9.8 , \text{m/s}^2} \approx 1.80 , \text{kg} \]
Now, we use this mass to find the gravitational force on Mars, where \( g_{\text{Mars}} = 3.71 , \text{m/s}^2 \):
\[ F_{\text{Mars}} = m \cdot g_{\text{Mars}} = 1.80 , \text{kg} \cdot 3.71 , \text{m/s}^2 \approx 6.68 , \text{N} \]
So, the gravitational force of the robotic helicopter on Mars is approximately 6.68 N.
Answer: 6.68 N
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