To find the initial value \( b \) of the linear function, we can use the slope-intercept form of a linear equation, which is given by:
\[ y = mx + b \]
Here, \( m \) is the slope of the line, \( (x, y) \) is a point on the line, and \( b \) is the y-intercept (the initial value).
Given:
- Rate of change \( m = -\frac{4}{7} \)
- Point \( (14, 3) \)
We can substitute the values of \( x \), \( y \), and \( m \) into the equation to find \( b \):
\[ 3 = -\frac{4}{7}(14) + b \]
First, calculate \( -\frac{4}{7} \times 14 \):
\[ -\frac{4 \times 14}{7} = -\frac{56}{7} = -8 \]
Now substitute this back into the equation:
\[ 3 = -8 + b \]
To solve for \( b \):
\[ b = 3 + 8 \] \[ b = 11 \]
Thus, the initial value \( b \) is:
\[ \boxed{11} \]