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Find the initial value of the linear function, given that the rate of change is m=−47 , and (14,3) is an (x,y) value of the lin...Question
Find the initial value of the linear function, given that the rate of change is m=−4/7
, and (14,3)
is an (x,y)
value of the linear function.(1 point)
Responses
b=15.71
b equals 15.71
b=11
b equals 11
b=−5
b equals negative 5
b=12.29
, and (14,3)
is an (x,y)
value of the linear function.(1 point)
Responses
b=15.71
b equals 15.71
b=11
b equals 11
b=−5
b equals negative 5
b=12.29
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the initial value \( b \) of the linear function, we can use the slope-intercept form of a linear equation, which is given by:
\[
y = mx + b
\]
Here, \( m \) is the slope of the line, \( (x, y) \) is a point on the line, and \( b \) is the y-intercept (the initial value).
Given:
- Rate of change \( m = -\frac{4}{7} \)
- Point \( (14, 3) \)
We can substitute the values of \( x \), \( y \), and \( m \) into the equation to find \( b \):
\[
3 = -\frac{4}{7}(14) + b
\]
First, calculate \( -\frac{4}{7} \times 14 \):
\[
-\frac{4 \times 14}{7} = -\frac{56}{7} = -8
\]
Now substitute this back into the equation:
\[
3 = -8 + b
\]
To solve for \( b \):
\[
b = 3 + 8
\]
\[
b = 11
\]
Thus, the initial value \( b \) is:
\[
\boxed{11}
\]
\[
y = mx + b
\]
Here, \( m \) is the slope of the line, \( (x, y) \) is a point on the line, and \( b \) is the y-intercept (the initial value).
Given:
- Rate of change \( m = -\frac{4}{7} \)
- Point \( (14, 3) \)
We can substitute the values of \( x \), \( y \), and \( m \) into the equation to find \( b \):
\[
3 = -\frac{4}{7}(14) + b
\]
First, calculate \( -\frac{4}{7} \times 14 \):
\[
-\frac{4 \times 14}{7} = -\frac{56}{7} = -8
\]
Now substitute this back into the equation:
\[
3 = -8 + b
\]
To solve for \( b \):
\[
b = 3 + 8
\]
\[
b = 11
\]
Thus, the initial value \( b \) is:
\[
\boxed{11}
\]
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