Question
Wave # Frequency
Wavelength
Wave 1
6.66 × 1014 Hz 450 nm
Wave 2 5.77 × 1014 Hz 520 nm
Wave 3 4.61 × 1014 Hz 650 nm
Wave 4 4.28 × 1014 Hz 700 nm
waves to answer the question.
Which wave contains the lowest energy?
(1 point)
wave 2
• wave 3
• wave 4
• wave 1
Wavelength
Wave 1
6.66 × 1014 Hz 450 nm
Wave 2 5.77 × 1014 Hz 520 nm
Wave 3 4.61 × 1014 Hz 650 nm
Wave 4 4.28 × 1014 Hz 700 nm
waves to answer the question.
Which wave contains the lowest energy?
(1 point)
wave 2
• wave 3
• wave 4
• wave 1
Answers
Answered by
GPT-4o mini
The energy of a photon can be calculated using the formula:
\[ E = h \times f \]
where:
- \( E \) is the energy,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \) J·s),
- \( f \) is the frequency of the wave.
Since energy is directly proportional to frequency, we can determine which wave contains the lowest energy by comparing their frequencies. The wave with the lowest frequency will have the lowest energy.
From the frequencies given:
- Wave 1: \( 6.66 \times 10^{14} \) Hz
- Wave 2: \( 5.77 \times 10^{14} \) Hz
- Wave 3: \( 4.61 \times 10^{14} \) Hz
- Wave 4: \( 4.28 \times 10^{14} \) Hz
Wave 4 has the lowest frequency of \( 4.28 \times 10^{14} \) Hz, which means it contains the lowest energy.
Therefore, the correct answer is:
- **wave 4**
\[ E = h \times f \]
where:
- \( E \) is the energy,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \) J·s),
- \( f \) is the frequency of the wave.
Since energy is directly proportional to frequency, we can determine which wave contains the lowest energy by comparing their frequencies. The wave with the lowest frequency will have the lowest energy.
From the frequencies given:
- Wave 1: \( 6.66 \times 10^{14} \) Hz
- Wave 2: \( 5.77 \times 10^{14} \) Hz
- Wave 3: \( 4.61 \times 10^{14} \) Hz
- Wave 4: \( 4.28 \times 10^{14} \) Hz
Wave 4 has the lowest frequency of \( 4.28 \times 10^{14} \) Hz, which means it contains the lowest energy.
Therefore, the correct answer is:
- **wave 4**
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