Question
What is the period of the function f left parenthesis t right parenthesis equals cosine left parenthesis 5 t plus Start Fraction pi over 2 End Fraction right parenthesis minus 3?
(1 point)
Responses
two fifths
Image with alt text: two fifths
three fifths
Image with alt text: three fifths
Start Fraction 2 pi over 5 End Fraction
Image with alt text: Start Fraction 2 pi over 5 End Fraction
π
π
2π
(1 point)
Responses
two fifths
Image with alt text: two fifths
three fifths
Image with alt text: three fifths
Start Fraction 2 pi over 5 End Fraction
Image with alt text: Start Fraction 2 pi over 5 End Fraction
π
π
2π
Answers
GPT-4o mini
To find the period of the function \( f(t) = \cos(5t + \frac{\pi}{2}) - 3 \), we focus on the cosine component, since the \(-3\) does not affect the period.
The general form of the cosine function is \( \cos(kx) \), where the period is given by:
\[
\text{Period} = \frac{2\pi}{|k|}
\]
In your case, the argument of the cosine function is \( 5t + \frac{\pi}{2} \). Here, \( k = 5 \).
Now, applying the formula for the period:
\[
\text{Period} = \frac{2\pi}{|5|} = \frac{2\pi}{5}
\]
Therefore, the period of the function \( f(t) \) is:
\[
\frac{2\pi}{5}
\]
So the correct response is:
\(\frac{2\pi}{5}\)
The general form of the cosine function is \( \cos(kx) \), where the period is given by:
\[
\text{Period} = \frac{2\pi}{|k|}
\]
In your case, the argument of the cosine function is \( 5t + \frac{\pi}{2} \). Here, \( k = 5 \).
Now, applying the formula for the period:
\[
\text{Period} = \frac{2\pi}{|5|} = \frac{2\pi}{5}
\]
Therefore, the period of the function \( f(t) \) is:
\[
\frac{2\pi}{5}
\]
So the correct response is:
\(\frac{2\pi}{5}\)