Asked by blue fire

i tried to find the derivative of this questions but it was way too hard, and i got it wrong on a test.. i need help

y=x4/3 - (sqr.root)5x + 4/x
Answered by Damon
do you mean
x^(4/3) - (5x)^.5 + 4 x^-1 ??
if so then
(4/3)x^(1/3) - .5(5x)^-.5 - 4x^-2
Answered by Anonymous
yah that is what i mean except for the first part of the questions is actually x^4/3 .. sorry lol
Answered by Anonymous
and i understand that part but is the derivative of x^4/3 = x^(1/12)?
Answered by Anonymous
oh and i just realized that looks like something different .. the first variable is x^4(divided by)3
Answered by Damon
d/dx [ (1/3) x^4 ] = (1/3)(4) x^3
= (4/3) x^3
Answered by Anonymous
(3x-4)^5 x(sqaure root)9x^2+4
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