Calculate and compare the surface area of sphere A , which has a radius of 6 in., and sphere B , which has a radius of 24 in. The formula for the surface area of a sphere is 4πr2 .(1 point)

Responses

Sphere A has a surface area of 36π in.2 and sphere B has a surface area of 576π in.2. This means that sphere B’s surface area is 16 times as large as sphere A’s.
Sphere upper A has a surface area of 36 pi in. squared and sphere upper B has a surface area of 576 pi in. squared . This means that sphere upper B ’s surface area is 16 times as large as sphere upper A ’s.

Sphere A has a surface area of 6π in.2 and sphere B has a surface area of 24π in.2. This means that sphere B’s surface area is 4 times as large as sphere A’s.
Sphere upper A has a surface area of 6 pi in. squared and sphere upper B has a surface area of 24 pi in. squared . This means that sphere upper B ’s surface area is 4 times as large as sphere upper A ’s.

Sphere A has a surface area of 144π in.2 and sphere B has a surface area of 2,304π in.2. This means that sphere B’s surface area is 16 times as large as sphere A’s.
Sphere upper A has a surface area of 144 pi in. squared and sphere upper B has a surface area of 2,304 pi in. squared . This means that sphere upper B ’s surface area is 16 times as large as sphere upper A ’s.

Sphere A has a surface area of 24π in.2 and sphere B has a surface area of 96π in.2. This means that sphere B’s surface area is 4 times as large as sphere A’s.
Sphere upper A has a surface area of 24 pi in. squared and sphere upper B has a surface area of 96 pi in. squared . This means that sphere upper B ’s surface area is 4 times as large as sphere upper A ’s.

1 answer

To calculate the surface area of spheres A and B, we can use the formula for the surface area of a sphere, which is:

\[ \text{Surface Area} = 4\pi r^2 \]

Calculating Sphere A:

  • Radius \( r = 6 \) in.

\[ \text{Surface Area of Sphere A} = 4\pi (6^2) = 4\pi (36) = 144\pi \text{ in}^2 \]

Calculating Sphere B:

  • Radius \( r = 24 \) in.

\[ \text{Surface Area of Sphere B} = 4\pi (24^2) = 4\pi (576) = 2304\pi \text{ in}^2 \]

Comparison of the Surface Areas:

  • Surface Area of Sphere A: \( 144\pi \)
  • Surface Area of Sphere B: \( 2304\pi \)

To find out how many times larger Sphere B's surface area is compared to Sphere A's surface area, we can use:

\[ \frac{\text{Surface Area of Sphere B}}{\text{Surface Area of Sphere A}} = \frac{2304\pi}{144\pi} = \frac{2304}{144} = 16 \]

This means that Sphere B’s surface area is 16 times as large as Sphere A’s.

So, the correct statement based on the calculations is:

Sphere A has a surface area of 144π in.² and sphere B has a surface area of 2,304π in.². This means that sphere B’s surface area is 16 times as large as sphere A’s.

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