Question

If a sample of 200 g of water must be boiled and the heat of vaporization of water is 2260 J/g, how much
heat is needed to cause this entire sample to boil into steam?
Answers below:
56800 J

411000 J

452000 J

395900 J

Answer 1

To find out how much heat is needed to boil the entire sample of water, you can use the formula:

\[
Q = m \cdot L
\]

where:
- \( Q \) is the heat required,
- \( m \) is the mass of the water, and
- \( L \) is the heat of vaporization.

In your case:
- \( m = 200 \, \text{g} \)
- \( L = 2260 \, \text{J/g} \)

Now, substituting the values into the formula:

\[
Q = 200 \, \text{g} \times 2260 \, \text{J/g}
\]

Calculating this gives:

\[
Q = 452000 \, \text{J}
\]

So, the amount of heat needed to boil the entire sample of water is \( 452000 \, \text{J} \).

The answer is \( 452000 \, \text{J} \).