If a sample of 200 g of water must be boiled and the heat of vaporization of water is 2260 J/g, how much

heat is needed to cause this entire sample to boil into steam?
Answers below:
56800 J

411000 J

452000 J

395900 J

1 answer

To find out how much heat is needed to boil the entire sample of water, you can use the formula:

\[ Q = m \cdot L \]

where:

  • \( Q \) is the heat required,
  • \( m \) is the mass of the water, and
  • \( L \) is the heat of vaporization.

In your case:

  • \( m = 200 , \text{g} \)
  • \( L = 2260 , \text{J/g} \)

Now, substituting the values into the formula:

\[ Q = 200 , \text{g} \times 2260 , \text{J/g} \]

Calculating this gives:

\[ Q = 452000 , \text{J} \]

So, the amount of heat needed to boil the entire sample of water is \( 452000 , \text{J} \).

The answer is \( 452000 , \text{J} \).