Question

A rectangle is drawn on a coordinate plane with vertices (0,0), (2,2), (9,−4), and (7,−6). Using the coordinates, what is the approximate area of the rectangle?(2 points) Responses 25.76 units² 25.76 units² 12.05 units² 12.05 units² 24.1 units² 24.1 units² 52.2 units²

Answers

GPT-4o mini
To find the area of the rectangle defined by the vertices \((0,0)\), \((2,2)\), \((9,-4)\), and \((7,-6)\), we first confirm that these points form a rectangle.

We start by identifying the lengths of the sides of the rectangle. The classical approach is to use the distance formula between pairs of points to confirm that opposite sides are equal and the angles are right angles.

1. Calculate the distances between the vertices:
- Distance between \((0,0)\) and \((2,2)\):
\[
d_1 = \sqrt{(2 - 0)^2 + (2 - 0)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}
\]
- Distance between \((2,2)\) and \((9,-4)\):
\[
d_2 = \sqrt{(9 - 2)^2 + (-4 - 2)^2} = \sqrt{7^2 + (-6)^2} = \sqrt{49 + 36} = \sqrt{85}
\]
- Distance between \((9,-4)\) and \((7,-6)\):
\[
d_3 = \sqrt{(7 - 9)^2 + (-6 + 4)^2} = \sqrt{(-2)^2 + (-2)^2} = \sqrt{4 + 4} = 2\sqrt{2}
\]
- Distance between \((7,-6)\) and \((0,0)\):
\[
d_4 = \sqrt{(0 - 7)^2 + (0 + 6)^2} = \sqrt{(-7)^2 + 6^2} = \sqrt{49 + 36} = \sqrt{85}
\]

From the calculations:
- Sides \(d_1\) and \(d_3\) are equal \((2\sqrt{2})\).
- Sides \(d_2\) and \(d_4\) are equal \((\sqrt{85})\).

Next, we verify that the sides meet at right angles using the slopes:
- Slope from \((0,0)\) to \((2,2)\) is \(1\).
- Slope from \((2,2)\) to \((9,-4)\):
\[
m = \frac{-4 - 2}{9 - 2} = \frac{-6}{7}
\]
- Slope from \((9,-4)\) to \((7,-6)\):
\[
m = \frac{-6 + 4}{7 - 9} = \frac{-2}{-2} = 1
\]
- Slope from \((7,-6)\) to \((0,0)\):
\[
m = \frac{0 + 6}{0 - 7} = \frac{6}{-7} = -\frac{6}{7}
\]

The calculations show that adjacent side slopes are negative reciprocals, confirming right angles.

Now we calculate the area \(A\) of the rectangle using the lengths of its sides:
- Length of the side: \(2\sqrt{2}\)
- Length of the other side: \(\sqrt{85}\)

The area \(A\) is given by:
\[
A = \text{(length)} \times \text{(width)} = (2\sqrt{2})(\sqrt{85}) = 2 \cdot \sqrt{170}
\]

To compute the approximate value:
\(\sqrt{170} \approx 13.0384\), hence:
\[
A \approx 2 \cdot 13.0384 \approx 26.0768
\]

Since none of the provided options match exactly, we identify the closest option, which is approximately \(25.76\) units². Thus, the answer is:

**25.76 units²**

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