Question
A colorblind female has a child with a male who is not colorblind. What are the chances of them having a daughter that is colorblind? (1 po
00%
100%
75%
50%
00%
100%
75%
50%
Answers
GPT-4o mini
To determine the chances of their daughter being colorblind, we need to consider how colorblindness is inherited. Colorblindness is typically inherited in an X-linked recessive manner.
1. A colorblind female has two X chromosomes with the colorblind allele (X^c X^c).
2. A male who is not colorblind has one X chromosome with the normal vision allele and one Y chromosome (X^N Y).
When they have children, the possible combinations of X and Y chromosomes from these parents are:
- From the mother (colorblind): X^c (the only option)
- From the father (not colorblind): X^N or Y
For their daughters:
- Daughters receive one X chromosome from each parent. Therefore, the combinations would be:
- X^c (from mother) and X^N (from father) → X^c X^N (not colorblind, but a carrier)
- It's not possible for a daughter to get an X from the father that is Y, because daughters get an X from both parents.
Thus, their daughters will all be X^c X^N, making them carriers of the colorblind allele but not colorblind themselves.
So, the chances of them having a daughter that is colorblind is **0%**.
Therefore, the answer is:
**0%**
1. A colorblind female has two X chromosomes with the colorblind allele (X^c X^c).
2. A male who is not colorblind has one X chromosome with the normal vision allele and one Y chromosome (X^N Y).
When they have children, the possible combinations of X and Y chromosomes from these parents are:
- From the mother (colorblind): X^c (the only option)
- From the father (not colorblind): X^N or Y
For their daughters:
- Daughters receive one X chromosome from each parent. Therefore, the combinations would be:
- X^c (from mother) and X^N (from father) → X^c X^N (not colorblind, but a carrier)
- It's not possible for a daughter to get an X from the father that is Y, because daughters get an X from both parents.
Thus, their daughters will all be X^c X^N, making them carriers of the colorblind allele but not colorblind themselves.
So, the chances of them having a daughter that is colorblind is **0%**.
Therefore, the answer is:
**0%**