Question
Solve the rational equation for x: 3x+x−3x=1x2
.(1 point)
Responses
x=3
x equals 3
x=1
x equals 1
x=0
x equals 0
x=±1
x equals plus or minus 1
.(1 point)
Responses
x=3
x equals 3
x=1
x equals 1
x=0
x equals 0
x=±1
x equals plus or minus 1
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the equation \( 3x + x - 3x = \frac{1}{x^2} \), we can first simplify the left side.
The left side simplifies as follows:
\[
3x + x - 3x = x
\]
Now the equation becomes:
\[
x = \frac{1}{x^2}
\]
To eliminate the fraction, we can multiply both sides by \( x^2 \) (assuming \( x \neq 0 \)):
\[
x^3 = 1
\]
Now, we can solve for \( x \) by taking the cube root of both sides:
\[
x = 1
\]
Now, we should also consider the case where \( x = 0 \), since we multiplied by \( x^2 \) which could potentially exclude \( x = 0 \) from the solutions.
When \( x = 0\):
The original equation \( 3x + x - 3x = \frac{1}{x^2} \) has an undefined right side because you cannot divide by zero.
Thus, \( x = 0 \) is not a valid solution.
The only solution we find is:
\[
x = 1
\]
Now, let's summarize the result. The correct answer is:
**x = 1** (or "x equals 1").
The left side simplifies as follows:
\[
3x + x - 3x = x
\]
Now the equation becomes:
\[
x = \frac{1}{x^2}
\]
To eliminate the fraction, we can multiply both sides by \( x^2 \) (assuming \( x \neq 0 \)):
\[
x^3 = 1
\]
Now, we can solve for \( x \) by taking the cube root of both sides:
\[
x = 1
\]
Now, we should also consider the case where \( x = 0 \), since we multiplied by \( x^2 \) which could potentially exclude \( x = 0 \) from the solutions.
When \( x = 0\):
The original equation \( 3x + x - 3x = \frac{1}{x^2} \) has an undefined right side because you cannot divide by zero.
Thus, \( x = 0 \) is not a valid solution.
The only solution we find is:
\[
x = 1
\]
Now, let's summarize the result. The correct answer is:
**x = 1** (or "x equals 1").
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