A ladder is resting against an outside wall of a building. The ladder is extended 23 feet, and reaches a distance of 17 feet up the wall. Using the inverse of sine, what is the angle of elevation formed where the base of the ladder rests on the ground? Round your answer to the nearest whole degree.(1 point)

1 answer

To find the angle of elevation formed at the base of the ladder, we can use the sine function.

The sine of an angle in a right triangle is defined as the ratio of the length of the opposite side to the hypotenuse. In this case:

  • The opposite side is the height the ladder reaches on the wall (17 feet).
  • The hypotenuse is the length of the ladder (23 feet).

We can set up the following equation using the sine function: \[ \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{17}{23} \]

To find the angle \( \theta \), we can use the inverse sine function: \[ \theta = \arcsin\left(\frac{17}{23}\right) \]

Calculating this: \[ \frac{17}{23} \approx 0.7391 \] Now, we find the arcsin of that value: \[ \theta \approx \arcsin(0.7391) \approx 47.2^\circ \]

Rounding to the nearest whole degree: \[ \theta \approx 47^\circ \]

Thus, the angle of elevation formed where the base of the ladder rests on the ground is approximately 47 degrees.