Question

Find the output,
\[h\], when the input,
\[x\], is
\[-18\].

\[h = 17+\dfrac{x}{6}\]
\[h=\]

Answer 1

To find the output \( h \) when the input \( x = -18 \), we will substitute \(-18\) into the equation \( h = 17 + \frac{x}{6} \).

Starting with the equation:

\[
h = 17 + \frac{x}{6}
\]

Substituting \( x = -18 \):

\[
h = 17 + \frac{-18}{6}
\]

Now, calculate \(\frac{-18}{6}\):

\[
\frac{-18}{6} = -3
\]

Now substitute back into the equation for \( h \):

\[
h = 17 - 3
\]

Finally, calculate \( h \):

\[
h = 14
\]

Therefore, the output \( h \) when the input \( x = -18 \) is

\[
\boxed{14}
\]